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October 1, 2014

October 1, 2014

Posted by **mina** on Friday, February 24, 2012 at 7:42pm.

- physics -
**drwls**, Saturday, February 25, 2012 at 1:29am1.22*(lambda)/D = (H/480)/L

H is the screen height.

L is the viewing distance for which the line width on the screen equals the eye's limit of resolution.

D = eye pupil diameter.

lambda = avg. wavelength = 570*10^-9 m

Solve for the desired L/H

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