posted by Anonymous on .
The quantity of antimony in a sample can be determined by an oxidation-reduction titration with an oxidizing agent. A 6.35-g sample of stibnite, an ore of antimony, is dissolved in hot, concentrated HCl(aq) and passed over a reducing agent so that all the antimony is in the form Sb3 (aq). The Sb3 (aq) is completely oxidized by 27.7 mL of a 0.130 M aqueous solution of KBrO3(aq). The unbalanced equation for the reaction is
BrO3^- + Sb^3+= Br^- + Sb^5+
Calculate the amount of antimony in the sample and its percentage in the ore.