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April 1, 2015

April 1, 2015

Posted by **MARÝA** on Friday, February 24, 2012 at 1:16pm.

a) What is the initial velocity component in the vertical direction?

b) What is the launch angle? (in degrees)

- PHYSÝCS -
**Steve**, Friday, February 24, 2012 at 1:50pmThe range for a projectile is

R = v^2/g sin2θ

Now, 5.87/v = cosθ

v = 5.87 secθ

31.1 = 5.87^{2}/9.8 sec^{2}θ * 2sinθcosθ

4.4227 = tanθ

θ = 77.26°

v = 26.62

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