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find f'(x) if f(x)=x^2*e^x*(3x-1)^3

  • Calculus -

    f(x) = (x^2) (e^x) (3x-1)^3

    if y = uvw
    then y' = u'(vw) + v'(uw) + w'(uv)

    I see 3 factors in f(x) to match that pattern.
    Does not look difficult, just carefully follow the above.

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