Posted by **amy** on Friday, February 24, 2012 at 3:06am.

The acceleration of a particle moving only on a horizontal plane is given by a= 3ti +4tj, where a is in meters per second-squared and t is in seconds.

At t = 0s, the position vector r= (20.0 m)i + (40.0 m)j locates the particle, which then has the velocity vector v= (5.000 m/s)i + (2.00 m/s)j

(a) What is the expression of its instantaneous velocity vector, as a function of time?

(b) What is the expression of its instantaneous position vector, as a function of time?

At t = 4s, what are :

(c) its position vector in unit-vector notation?

(d) the angle between its direction of travel and the positive direction of the x axis?

## Answer this Question

## Related Questions

- physics - The acceleration of a particle moving only on a horizontal plane is ...
- Physics - The acceleration of a particle moving only on a horizontal xy plane is...
- Physics - The acceleration of a particle moving only on a horizontal xy plane is...
- Physics - The acceleration of a particle moving only on a horizontal xy plane is...
- Physics - A particle moved along the x axis with a constant acceleration of -85....
- physics - A particle experiences a constant acceleration that is south at 2.50 ...
- Physics - A particle starts from the origin with velocity 2i m/s at t = 0 and ...
- Physics-can anyone check my work? - A particle starts from the origin with ...
- Calculus - The position of a particle moving on a horizontal line is given by s(...
- physics - The position vector r of a particle moving in the xy plane is r=2ti+...