How much water should be added to 20oz of a 15% solution of alcohol to dilute it to s 10% alcohol solution?

Let the number of oz of added H2O be x.

The mass of alcohol in the solution stays the same. Only H2O is added.

0.20*15 = 0.10(20 + x)

Solve for x.

3 = 2 + 0.1x

x = 1/0.1 = 10 oz

To dilute 20oz of a 15% solution of alcohol to a 10% alcohol solution, you need to add water. We can start by calculating the amount of alcohol in the initial solution and the desired final solution.

In the initial solution, there is:
(15/100) * 20oz = 3oz of alcohol

Now, let's find out how much water should be added to reach the desired final solution with 10% alcohol concentration.

Let "x" represent the amount of water to be added (in ounces).

In the final solution, the total volume will be 20oz + x, and the amount of alcohol will be 3oz.

So we can set up the following equation:

3oz / (20oz + x) = 10/100

Now we can solve for "x":

0.3 = 2 + 0.1x
0.1x = 0.3 - 2
0.1x = -1.7
x = -1.7 / 0.1
x ≈ -17

It seems like the equation resulted in a negative value, which is not possible in this situation. It suggests that the available 20oz solution of 15% alcohol cannot be diluted to a 10% alcohol solution solely by adding water.

To determine how much water should be added to a 20oz solution of 15% alcohol to create a 10% alcohol solution, we can follow these steps:

Step 1: Understand the problem.
We have a 20oz solution containing 15% alcohol. We want to dilute it with water to create a 10% alcohol solution. We need to find the amount of water that needs to be added.

Step 2: Calculate the amount of alcohol in the original solution.
Since the original solution is 15% alcohol, we can calculate that by multiplying the volume (20oz) by the percentage (15%). This gives us 20oz * 0.15 = 3oz of alcohol in the original solution.

Step 3: Determine the final volume of the diluted solution.
We want to end up with a 10% alcohol solution, which means the final volume will be the same as the original volume (20oz). Therefore, the water added will be the difference between the final volume and the alcohol volume in the original solution: 20oz - 3oz = 17oz of water needed.

So, to dilute the 20oz solution of 15% alcohol to a 10% alcohol solution, you should add 17oz of water.