Posted by **David** on Friday, February 24, 2012 at 1:20am.

This question is from my workbook (Pre-Calculus 11). Can someone please help me understand it?

Suppose theta is an angle in standard position with terminal army in quadrant III and tan theta = 6/3. Determine the exact calues of the other two primary trigonometric rations.

In quardatn III, x is ______ and y is ________ (r is always positive).

I don't understand how to draw the triangle for reference.

Any help will be greatly appreciated. Thank you.

- Math -
**man**, Friday, February 24, 2012 at 7:57am
(-6r)-5=7-12r

- Math -
**Steve**, Friday, February 24, 2012 at 10:52am
tan = y/x

since both x and y are negative in QIII, then you must have

tan = 6/3 = -6/-3,

so y = -6 and x = -3

now, r = 3sqrt(5)

sin = y/r

cos = x/r

just plug and chug

## Answer This Question

## Related Questions

- trig - If theta is the measure of an angle in standard position with the given ...
- math - The terminal side of an angle theta in standard position coincides with ...
- math - Another: theta is a second quadrant angle in standard position and tan ...
- Trig - The point (-5/12) is on the terminal side of an angle theta in standard ...
- Pre-Calc/Math - if (0,-7) lies on the terminal side of angle theta in standard ...
- Pre-Calculus ( Trigonometry) - The point P(k, 24) is 25 units from the origin. ...
- Math - 1. Let (-7, 4) be a point on the terminal side of (theta). Find the exact...
- Pre-Calculus-check answers - If cos theta = 0.8 and 270<theta<360, find ...
- math - if csc theta= -5/3 and theta has its terminal side in quadrant III, find ...
- Pre-Calc - if (0,-7) lies on the terminal side of angle theta in standard ...

More Related Questions