Posted by **David** on Friday, February 24, 2012 at 1:20am.

This question is from my workbook (Pre-Calculus 11). Can someone please help me understand it?

Suppose theta is an angle in standard position with terminal army in quadrant III and tan theta = 6/3. Determine the exact calues of the other two primary trigonometric rations.

In quardatn III, x is ______ and y is ________ (r is always positive).

I don't understand how to draw the triangle for reference.

Any help will be greatly appreciated. Thank you.

- Math -
**man**, Friday, February 24, 2012 at 7:57am
(-6r)-5=7-12r

- Math -
**Steve**, Friday, February 24, 2012 at 10:52am
tan = y/x

since both x and y are negative in QIII, then you must have

tan = 6/3 = -6/-3,

so y = -6 and x = -3

now, r = 3sqrt(5)

sin = y/r

cos = x/r

just plug and chug

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