Posted by David on Friday, February 24, 2012 at 1:20am.
(-6r)-5=7-12r
tan = y/x
since both x and y are negative in QIII, then you must have
tan = 6/3 = -6/-3,
so y = -6 and x = -3
now, r = 3sqrt(5)
sin = y/r
cos = x/r
just plug and chug
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