Posted by David on Friday, February 24, 2012 at 1:20am.
This question is from my workbook (PreCalculus 11). Can someone please help me understand it?
Suppose theta is an angle in standard position with terminal army in quadrant III and tan theta = 6/3. Determine the exact calues of the other two primary trigonometric rations.
In quardatn III, x is ______ and y is ________ (r is always positive).
I don't understand how to draw the triangle for reference.
Any help will be greatly appreciated. Thank you.

Math  man, Friday, February 24, 2012 at 7:57am
(6r)5=712r

Math  Steve, Friday, February 24, 2012 at 10:52am
tan = y/x
since both x and y are negative in QIII, then you must have
tan = 6/3 = 6/3,
so y = 6 and x = 3
now, r = 3sqrt(5)
sin = y/r
cos = x/r
just plug and chug
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