Posted by Grant on Friday, February 24, 2012 at 12:08am.
A farmer with 700 ft of fencing wants to enclose a rectangular area and then divide it into four pens with fencing parallel to one side of the rectangle. What is the largest possible total area of the four pens?

Calc 1  Grant, Friday, February 24, 2012 at 12:55am
Answer is 12250

Calc 1  Steve, Friday, February 24, 2012 at 10:49am
so, is there a question somewhere in there?

Calc 1  MathMate, Friday, February 24, 2012 at 1:43pm
What is the largest possible total area of the four pens?
Let x=shorter side of the big rectangle.
and y=long side of the big rectangle
Fence required = 5x+2y=700 => y=3505x/2
Total area of pens
A=xy
=x(3505x/2)
To get the maximum area, we equate dA/dx=0
dA/dx = 3505x = 0, or
x=70
y=3505x/2 = 175
Maximum total area=xy=70*175=12250'

Calc 1  Tina, Wednesday, April 17, 2013 at 1:06pm
Can someone draw the picture?
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