Posted by Grant on Friday, February 24, 2012 at 12:08am.
Answer is 12250
so, is there a question somewhere in there?
What is the largest possible total area of the four pens?
Let x=shorter side of the big rectangle.
and y=long side of the big rectangle
Fence required = 5x+2y=700 => y=350-5x/2
Total area of pens
A=xy
=x(350-5x/2)
To get the maximum area, we equate dA/dx=0
dA/dx = 350-5x = 0, or
x=70
y=350-5x/2 = 175
Maximum total area=xy=70*175=12250'
Can someone draw the picture?
Can someone draw the picture?
Related Questions
math - a farmer with 10,000 meters of fencing wants to enclose a rectangular ...
algebra - A farmer decides to enclose a rectangular garden, using the side of a ...
Calculus - A pig farmer wants to enclose a rectangular area and then divide it ...
Calculus - A ostrich farmer wants to enclose a rectangular area and then divide ...
algebra - A farmer decides to enclose a rectangular garden, using the side of a ...
Math - a farmer wants to put a fence around a rectangular field and then divide ...
Calculus - Consider the following problem: A farmer with 810 ft of fencing wants...
Algebra - A farmer decides to enclose a rectangular garden, using the side of a ...
Algebra 2 - A farmer has 120 ft. of fencing available to enclose 2 adjacent ...
MATH - A kennel owner has 164 ft of fencing to enclose a rectangular region. He ...
For Further Reading