Whatis the surface area of the right square pyramid in square meters?
Dimensions:
Base/length: 6 meters
Slant height: 5 meters
I know the formula is S.A.=1/2P "l"+B. I don't know what P or B is.....
P=perimeter of the base (=4*6 m)
B=area of base (4*4 m^2)
"I"=slant height (5 m)
To find the surface area (S.A.) of a right square pyramid, you need to know the base length (B) and the slant height (l). The formula you mentioned is correct: S.A. = 1/2P "l" + B. Let's break down the formula further:
1. Base Length (B): In a square pyramid, the base is a square. You mentioned that the length of the base is 6 meters. Since the base is square, all sides are equal, so B = 6 meters.
2. Slant Height (l): The slant height is the height from the apex (top) of the pyramid to the midpoint of any side. You mentioned that the slant height is 5 meters, so l = 5 meters.
Now, we need to find the perimeter (P) of the base.
3. Perimeter of the Base (P): Since the base is a square, the perimeter is calculated by multiplying the length of one side (let's call it s) by 4 (since there are four sides in a square). In this case, s = 6 meters, so P = 4s = 4 * 6 = 24 meters.
Now that we know the values, we can substitute them into the formula to find the surface area:
S.A. = 1/2P "l" + B
S.A. = 1/2 * 24 meters * 5 meters + 6 meters
S.A. = 12 meters * 5 meters + 6 meters
S.A. = 60 square meters + 6 square meters
S.A. = 66 square meters
Therefore, the surface area of the right square pyramid is 66 square meters.