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posted by missy on Thursday, February 23, 2012 at 6:31pm.
Find the maximum or minimum for f(x)=3x^2+x+1
using Calculus ... f'(x) = 6x + 1 6x+1 = 0 x = -1/6 f(-1/6) = 3(1/36) - 1/6 + 1 = 11/12 since the parabola opens upwards, the minimum value is 11/12
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