There are 37 students in an algebra class. there are 9 more girls than boys. how many boys and how many girls are in the class? I have to use systems of equations to solve.

Let b = number of boys.

b + 9 = girls

b + b + 9 = 37

2b = 37 - 9

b = 28/2

b = 14

To solve this problem using systems of equations, let's assume the number of boys in the class is represented by 'b' and the number of girls by 'g'.

We know that there are 37 students in total, so we can write the equation:

b + g = 37

We are also given that there are 9 more girls than boys. This can be represented as:

g = b + 9

Now we have a system of equations:

b + g = 37
g = b + 9

To solve this system, we can use the substitution method. Let's solve the second equation for 'b':

g = b + 9
b = g - 9

Substituting this expression for 'b' in the first equation:

(g - 9) + g = 37
2g - 9 = 37
2g = 37 + 9
2g = 46
g = 46/2
g = 23

Now we can substitute this value of 'g' back into the equation for 'b' to find its value:

b = g - 9
b = 23 - 9
b = 14

Therefore, there are 14 boys and 23 girls in the algebra class.