Thursday

January 29, 2015

January 29, 2015

Posted by **GRISSELL** on Thursday, February 23, 2012 at 2:54pm.

k= 18 N/m

x initial = o m

x final = 0.08m

Useing Hooke's law to calculate the force needed to stretch this spring 8 cm.

- PHYSICS -
**Damon**, Thursday, February 23, 2012 at 3:10pmF = k x = 18 * .08

**Answer this Question**

**Related Questions**

Physics - When a 2.00-kg object is hung vertically on a certain light spring ...

Physics - When a 3.00-kg object is hung vertically on a certain light spring ...

physics - When a 2.60-kg object is hung vertically on a certain light spring ...

physics - Sir Robert Hooke (1635-1703), studied the elastic properties of ...

Physics - The force required to stretch a Hooke’s-law spring varies from 0 N to ...

Physics - The force required to stretch a Hooke’s-law spring varies from 0 N to ...

physics - The force required to stretch a Hooke’s-law spring varies from 0 N to ...

physics - When a 2.50-kg object is hung vertically on a certain light spring ...

physics - The force required to stretch a Hooke’s-law spring varies from 0 N to ...

Physics - Hooke's law states that it takes a force equal to kΔx is required...