I need help solve the equation by fractions
8/(21-y) = 12/(y+19)
I think the answer is y = 5, i just need to know how to do work out. i done some solution like this
first multiply by(21-y)(y+19)(assuming that y = 21 and y = 19:
(21-y)(y+19)8/(21-y) = (21-y)(y+19)12/(y+19)
then cancel and multiply out the brackets:
8(y+19) = 12(21-y)
that is
8x+152 = 12x-96
finally,rearrange the equation as
160x = 104
y=5 is correct.
To multiply by (21-y)(y+19), y must not equal 21 nor -19.
Correct until
8(y+19) = 12(21-y)
Expand:
8y+152=-12y+252
20y=100
y=5
To solve the equation 8/(21-y) = 12/(y+19) by fractions, you have made a mistake in your calculations. Let's go through the correct steps together:
Step 1: Cross multiply the fractions.
This means multiplying the numerator of the first fraction with the denominator of the second fraction, and vice versa:
8(y + 19) = 12(21 - y)
Step 2: Distribute the terms on both sides of the equation:
8y + 152 = 252 - 12y
Step 3: Combine like terms on both sides:
8y + 12y = 252 - 152
20y = 100
Step 4: Divide by 20 to solve for y:
y = 100/20
Simplifying the expression gives you:
y = 5
So, the correct solution for the equation is y = 5.