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January 31, 2015

January 31, 2015

Posted by **jubillee** on Wednesday, February 22, 2012 at 7:35pm.

- Algebra -
**MathMate**, Thursday, February 23, 2012 at 12:02amLet the middle odd integer be n, then the three consecutive integers are n-2, n, and n+2.

Their sum is (n-2)+n+(n+2)=3n

If the sum is 5 more than four times the larger, then

3n=4(n+2)+5

Solve for n.

(Note: n is a negative integer!)

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