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A solution is made by adding 0.100 mole of ethyl ether to 0.841 mole of ethyl alcohol. If the vapor pressure of ethyl ether and ethyl alcohol at 20oC are 375 torr and 20.0 torr, respectively, the vapor pressure of the solution at 20oC (assuming ideal behavior) is:

  • chemistry - ,

    total moles = mol ether + mol EtOH
    Xether = moles ether/total mols
    XEtOH = moles EtOH/total moles

    pether = Xether*Po ether
    pEtOH = XEtOH*Po EtOH
    Total vapor pressure above the solution = pether + pEtOH.

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