jasmine bought 26 pieces of fruit.she bought 6 oranges.she bought twice as many apples as oranges,and twice as many oranges as bananas.she also bought some pears.

Please complete the question.

Total Fruit = 26

as per condition
O = 6 => O = 6
A = 2O => A = 2.6 => A = 12
O = 2B => B = O/2 => B = 6/2 => B = 3
O+A+B = 6+12+3 => O+A+B = 21
P = T.F - (O+A+B) => P= 26 - 21 => P=5

We have six oranges.

Apples= 6x2
Banana = 6/2
Pears: 26- (apple+bananas + oranges)
Pears = 26-21
Pears: 5
Basically, this is really easy. I know it's 2021, about a decade later, but this is for anyone else who sees this problem. It's actually from a fourth-grade state test, released questions. The state test occurred in 2005.

To find out how many pears Jasmine bought, we need to determine the quantities of oranges, apples, and bananas first.

We're given that Jasmine bought 6 oranges. Let's denote the number of oranges as O = 6.

Next, we're told that Jasmine bought twice as many apples as oranges. Therefore, the number of apples is A = 2 * O. Since O = 6, we can substitute the value: A = 2 * 6 = 12

Lastly, we're informed that Jasmine bought twice as many oranges as bananas. So, the number of bananas is B = O/2. Substituting O = 6, we get: B = 6/2 = 3.

Now, we can find the number of pears Jasmine bought. The total number of fruit is given as 26, and we know the quantities of oranges, apples, bananas, and pears.

Total fruit = O + A + B + P, where P represents the number of pears.

Substituting the known quantities: 26 = 6 + 12 + 3 + P.

Rearranging the equation: P = 26 - 6 - 12 - 3 = 5.

Therefore, Jasmine bought 5 pears.