algebra 2
posted by Gabby! on .
solve the equation m^6 64=0

M^664=0
M^6=64
take 6root of M^6 to get M
take 6root of 64 which =+or2
so,M=+2 
(m^24)(m^4+4m^2+16) = 0
(m+2)(m2)(m^4+4m^2+16) = 0
so, m = 2 and 2 are solutions
Now we have a quadratic in m^2, so
m^2 = [4 +/ sqrt(48)]/2
= 2 +/ 4sqrt(3)i
m = +/ 1 +/ sqrt(3)i