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Posted by on Wednesday, February 22, 2012 at 12:24am.

Two small charged balls have a repulsive force of 0.12 N when they are separated by a distance of 0.85 m. The balls are moved closer together, until the repulsive force is 0.60 N. How far apart are they now?

  • PHYSICS help please - , Wednesday, February 22, 2012 at 12:30am

    For the repulsive force to increase by a factor of 5, the distance must decrease by a factor of sqrt5 = 2.236

    That would make the new distance 0.380 m

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