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July 31, 2014

July 31, 2014

Posted by **Daniel** on Wednesday, February 22, 2012 at 12:04am.

I'm really lost at how to do tackle this problem. I know that an electric field is zero at infinity for positive charges but I don't know how to show it.

- physics -
**drwls**, Wednesday, February 22, 2012 at 12:51amThe horizontal E-field component at the empty corner is due to q1 and q only. For it to be zero,

q1/4d^2 = [q/(5d^2)]*(2/sqrt5)

The last term in parentheses is the cosine of the angle that the diagonal makes with the horizontal axis.

q1 = (4/5)(2/sqrt5) = 0.7155 q

The vertical E-field component at the empty corner is due to q2 and q only. For it to be zero,

q2/d^2 = [q/(5d^2)]*(1/sqrt5)

q2 = (1/5)(1/sqrt5) q = 0.0894 q

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