A bomber flies horizontally with a speed of
114 m/s relative to the ground. The altitude
of the bomber is 2120 m and the terrain is
level. Neglect the effects of air resistance.
The acceleration of gravity is 9.8 m/s2 .
A bomber flies horizontally with a speed of
114 m/s relative to the ground. The altitude
of the bomber is 2120 m and the terrain is
level. Neglect the effects of air resistance.
The acceleration of gravity is 9.8 m/s2 .
You stated the same facts twice but never asked a question.
To find the time it takes for the bomber to hit the ground, we can use the equation for free fall:
h = (1/2) * g * t^2
where:
h = altitude (2120 m)
g = acceleration due to gravity (9.8 m/s^2)
t = time
We can rearrange the equation to solve for time:
t^2 = (2h) / g
Taking the square root of both sides, we get:
t = √[(2h) / g]
Substituting the given values:
t = √[(2 * 2120) / 9.8]
Calculating:
t ≈ √(4340 / 9.8)
t ≈ √443.877
t ≈ 21 seconds
Therefore, it takes approximately 21 seconds for the bomber to hit the ground.