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Algebra

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A reguluation racquetball court should have a perimeter of 120 ft, with a length that is twice the width find the length and the width of a court

  • Algebra - ,

    W = Width

    L = Length

    P = Perimeter


    L = 2 W


    P = 2 L + 2 W = 120 ft

    2 * 2 W + 2 W = 120

    4 W + 2 W = 120

    6 W = 120 Divide both sides by 6

    W = 120 / 6

    W = 20 ft

    L = 2 W

    L = 2 * 20

    L = 40 ft

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