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algebra

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One side of a triangle is half the longest side. The third side is 9 meters less than the longest side. The perimeter is 61 meters. Find all three sides.

  • algebra -

    c = the longest side

    a = c / 2

    b = c - 9


    P = a + b + c = 61 m

    a + b + c = 61

    c / 2 + c - 9 + c = 61 Multiply both sides by 2

    c + 2 c - 18 + 2 c = 122

    5 c - 18 = 122

    5 c = 122 + 18

    5 c = 140 Divide both sides by 5

    c = 140 / 5

    c = 28 m

    a = c / 2

    a = 28 / 2

    a = 14 m

    b = c - 9

    b = 28 - 9

    b = 19 m

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