algebra
posted by Anonymous .
How do i solve 8y to the 2nd plus 30y plus 13

I assume you mean you want to solve
8y^2 + 30y + 13 = 0
You know that if it factors, it will have factors of the form
(8y+?)(y+)
or
(4y+?)(2y+?)
where ? is either 1 or 13. You also need the inside and outside products to add to 30y.
(4y+13)(2y+1) does the trick.
So, y = 13/4 or 1/2