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October 26, 2014

October 26, 2014

Posted by **Anonymous** on Tuesday, February 21, 2012 at 9:35pm.

- algebra -
**Steve**, Wednesday, February 22, 2012 at 10:23amI assume you mean you want to solve

8y^2 + 30y + 13 = 0

You know that if it factors, it will have factors of the form

(8y+?)(y+)

or

(4y+?)(2y+?)

where ? is either 1 or 13. You also need the inside and outside products to add to 30y.

(4y+13)(2y+1) does the trick.

So, y = -13/4 or -1/2

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