Posted by **math** on Tuesday, February 21, 2012 at 8:48pm.

A rectangular garden of area 75 sq ft is to be surrounded on 3 sides by a brick wall costing $12 per foot and on one side by a fence costing $7 per foot. Find the dimensions of the garden that the cost of the materials is minimized Read more: A rectangular garden of area 75 sq ft is to be surrounded on 3 sides by a brick wall costing $10 per foot and on one side by a fence costing $5 per foot. Find the dimensions of the garden that the cost of the materials is minimized

- Calculus -
**MathMate**, Tuesday, February 21, 2012 at 9:18pm
Let the dimensions of the garden be

x (fence side) and 75/x (since the area is 75).

So the total cost, C(x)

= 7x+2*12(75/x)+12(7)

= 7x+1800/x+84

To find the minimum cost (at the expense of the shape of the garden)

we calculate

C'(x)=0

7-1800/x^2=0

x=sqrt(1800/7)=16.04'

75/x=4.68'

- Calculus -
**math**, Tuesday, February 21, 2012 at 9:22pm
the answer is wrong

- Calculus -
**Reiny**, Tuesday, February 21, 2012 at 9:22pm
let the side with the fence be x ft long, then the perpendicular side is 75/x

cost = 7x + 12(75/x)

d(cost)/dx = 7 - 900/x^2 = 0 for a min of cost

7 = 900/x^2

x^2 = 900/7

x = 30/√7 = appr 11.339

so the garden has to be 11.339 by 75/11.339

or 11.34 by 6.61

check: 11.34 x 6.61 = 74.96 , not bad

cost = 7(11.339) + 900/11.339 = 158.75 --- minimum cost

let x = 11 , cost = 7(11) + 900/11 = 158.82 , a higher cost

let x = 11.6, cost = 7(11.5) + 900/11.5 = 158.75 -- just a bit higher

MY answer is correct

- Calculus -
**MathMate**, Tuesday, February 21, 2012 at 11:05pm
You're right, I mis-calculated the cost of the fourth side (12(7) instead of 12x).

Let the dimensions of the garden be

x (fence side) and 75/x (since the area is 75).

Since there are *four* sides to the garden:

So the total cost, C(x)

= 7x+2*12(75/x)+12(**x**)

= 19x+1800/x

To find the minimum cost (at the expense of the shape of the garden)

we calculate

C'(x)=0

19-1800/x^2=0

x=sqrt(1800/19)=9.733' (fence side)

75/x=7.706' (wall side)

C(sqrt(1800/19))=$369.86

## Answer This Question

## Related Questions

- Business Calculus - A rectangular garden of area 480 square feet is to be ...
- Calculus - 1) A rectangular page is to contain 16 square inches of print. The ...
- calculus - A landscape architect wishes to enclose a rectangular garden on one ...
- calculus - A landscape architect wished to enclose a rectangular garden on one ...
- Calculus - A landscape architect wished to enclose a rectangular garden on one ...
- Calculus - ABC Daycare wants to build a fence to enclose a rectangular ...
- Applied Calculus - A hardware store owner chooses to enclose an 800 square foot ...
- optimization calcus - A rectangular rose garden will be surrounded by a brick ...
- math - a landscape architect plans to enclose a 3000 square foot rectangular ...
- Calculus - Optimization - A fence is to be built to enclose a rectangular area ...

More Related Questions