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Binomial problems: Basic
Anita's, a fast-food chain specializing in hot dogs and garlic fries, keeps track of the
proportion of its customers who decide to eat in the restaurant (as opposed to ordering the
food "to go"), so it can make decisions regarding the possible construction of in-store play
areas, the attendance of its mascot Sammy at the franchise locations, and so on. Anita's
reports that 48% of its customers order their food to go. If this proportion is correct, what
is the probability that, in a random sample of 4 customers at Anita's, exactly 3 order their
food to go?

  • Math - ,

    This is a binomial distribution:

    p = .48, q = 1 - p = .52

    The probability P{X} of exactly 4 customers from 5, will order food to go is:

    P{X = 4} = (5 C 4)((.48)^4)((1 - .48)^1)

  • Math - ,

    0.37

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