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April 16, 2014

Homework Help: Chemistry

Posted by Kay on Tuesday, February 21, 2012 at 5:18pm.

For the reaction, 2 XO + O2 = 2 X02, some data obtained from measurement of the initial rate of reaction at varying concentrations are given below.

run # [XO] [O2] rate,mol L-l s-1
1 0.010 0.010 2.5
2 0.010 0.020 5.0
3 0.030 0.020 45.0

The rate law is therefore

a. rate = k[XO]2 [O2]
b. rate = k[XO][O2]2
c. rate = k[XO][O2]
d. rate = k[XO]2 [O2] 2
e. rate = k[XO]2 / [O2] 2

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