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Posted by on Tuesday, February 21, 2012 at 3:54pm.

A chemist has a solution that is 20% HIC and a solution that is 50% HCI. How much of each solution should be mixed to attain 300ml of a solution that is 30% HCI?

  • algebra - , Tuesday, February 21, 2012 at 4:58pm

    let the amount of the 20% solution used be x ml
    then the amount of the 50% solution used is 300-x m.

    solve for x ....
    .2x + .5(300-x) = .3(300)
    times 10
    2x + 5(300-x) = 3(300)

    take it from there

  • algebra - , Tuesday, February 21, 2012 at 5:00pm

    It may help to set up a table for these kinds of problems:

    ............Amount.....%....HCl
    Solution 1....x......0.2....0.2x
    Solution 2...300-x...0.5....0.5(300-x)
    Mixture......300.....0.3....0.3(300)

    Equation:
    0.2x + 0.5(300-x) = 0.3(300)

    Solve for x. (Be sure to list the amount of both solutions!)

    I hope this helps.

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