A purse contains $3.65 in quaters and dimes. There are 9 more quaters than dimes. Find the number of quaters and dimes.
dimes ---- x
quarters -- x+9
solve for x .....
10x + 25(x+9) = 365
a purse contains $2.95 in quarters and dimes. There are 9 more quarters than dimes. Find the number of quarters and dimes
To solve this problem, we can set up a system of equations based on the given information.
Let's assume the number of dimes is x.
Since there are 9 more quarters than dimes, the number of quarters would be x + 9.
Now, let's calculate the value of the coins:
The value of the dimes would be 0.10x (since each dime is worth $0.10).
The value of the quarters would be 0.25(x + 9) (since each quarter is worth $0.25).
According to the problem, the total value of the coins is $3.65. So we can set up the equation:
0.10x + 0.25(x + 9) = 3.65
Now, we can solve this equation to find the values of x (number of dimes) and x + 9 (number of quarters).
0.10x + 0.25x + 2.25 = 3.65
0.35x + 2.25 = 3.65
0.35x = 3.65 - 2.25
0.35x = 1.40
x = 1.40 / 0.35
x = 4
So, the number of dimes is 4 and the number of quarters is 4 + 9 = 13.