Posted by **Erin** on Tuesday, February 21, 2012 at 1:35pm.

You operate a gaming Web site, where users must pay a small fee to log on. When you charged $3 the demand was 520 log-ons per month. When you lowered the price to $2.50, the demand increased to 780 log-ons per month.

(a) Construct a linear demand function for your Web site and hence obtain the monthly revenue R as a function of the log-on fee x.

R(x)=

(b) Your Internet provider charges you a monthly fee of $10 to maintain your site. Express your monthly profit P as a function of the log-on fee x.

P(x)=

[What formula do I use to solve this? How should I approach it?]

Determine the log-on fee you should charge to obtain the largest possible monthly profit.

x=$

[Do I plug in some number?]

What is the largest possible revenue?

[How do I find this?]

Thank you.

- Algebra -
**Steve**, Tuesday, February 21, 2012 at 6:56pm
If we have a linear demand function, it will look like

R = mx+b where x is the price and y is the demand at that price.

780 = 2.5m + b

520 = 3m + b

so,

-260 = .5m

m = -520

b = 2080

R = 2080 - 520x

profit = revenue - cost

revenue = demand * price

P = R*x - 10

P = 2080x - 520x^2 - 10

you have a parabola, where the vertex is at x =

-b/2a = 2080/1040 = 2

P(2) = 2070

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