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April 18, 2014

April 18, 2014

Posted by **jessica** on Tuesday, February 21, 2012 at 11:27am.

- algebra -
**Henry**, Wednesday, February 22, 2012 at 6:43pma. C(t) = 36,500(0.82)^0 = $36,500.

b. C(t) = 36500(0.82)^4 = $16,502.44.

c. 36,500(0.82)^t = $5000.

(0.82)^t < 5000 / 36500.

(0.82)^t = 0.1370.

t*Log(0.82) = Log(0.1370).

t = Log(0.1370) / Log(0.82).

t = 10 yrs.

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