Posted by juan on Tuesday, February 21, 2012 at 1:57am.
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[f(.1)-f(0)]/.1 = .1
so, f'(0) is about .1
[f(.1)-f(0)]/.1 = .1
[f(.2)-f(.1)]/.1 = .5
so, f''(0) is about .4
looks like f(x) = 10x + x^2 + 4/3 x^3 ...
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