Question

How do I find JK for J(3, 8)and K(-1, 4)? Please help!

Answer 1

J(3,8),K(-1,4).

(JK)^2 = (x2-x1)^2 + (y2-y1)^2.
(JK)^2 = (-1-3)^2 + 4-8)^2.
(JK)^2 = 16 + 16 = 32.
JK = sqrt32 = 5.66.