Posted by **help** on Monday, February 20, 2012 at 10:24pm.

Sand is poured onto a level piece of ground at the rate of 0.25 m^3/min and forms a conical pile whose height is equal to its base diameter. How fast is the height increasing at the instant when the height is 0.50 m? V = 1/3(pi)(r^2)h

I got 3/pie, is that correct?

- Calculus -
**Reiny**, Monday, February 20, 2012 at 11:09pm
I got 4/π

let the radius be r, then the height is 2r

V= (1/3)πr^2 h

= (1/3)πr^2(2r)

= (2/3)πr^3

dV/dt = 2π r^2 dr/dt

when 2r=.5

r = .25 and dV/dt = .25

1/4 = 2π(1/16) dr/dt

times 8

2 = π dr/dt

dr/dt = 2/π

d(2r)/dt = d(height)/dt = 4/π

- Calculus -
**help**, Tuesday, February 21, 2012 at 2:02am
Thank you!

- Calculus -
**Anonymous**, Monday, February 23, 2015 at 4:03pm
Where did you get 8 from?

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