Posted by help on Monday, February 20, 2012 at 10:24pm.
Sand is poured onto a level piece of ground at the rate of 0.25 m^3/min and forms a conical pile whose height is equal to its base diameter. How fast is the height increasing at the instant when the height is 0.50 m? V = 1/3(pi)(r^2)h
I got 3/pie, is that correct?

Calculus  Reiny, Monday, February 20, 2012 at 11:09pm
I got 4/π
let the radius be r, then the height is 2r
V= (1/3)πr^2 h
= (1/3)πr^2(2r)
= (2/3)πr^3
dV/dt = 2π r^2 dr/dt
when 2r=.5
r = .25 and dV/dt = .25
1/4 = 2π(1/16) dr/dt
times 8
2 = π dr/dt
dr/dt = 2/π
d(2r)/dt = d(height)/dt = 4/π

Calculus  help, Tuesday, February 21, 2012 at 2:02am
Thank you!

Calculus  Anonymous, Monday, February 23, 2015 at 4:03pm
Where did you get 8 from?
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