Posted by Anonymous on Monday, February 20, 2012 at 10:22pm.
Simplify #3:
[cosxsin(90x)sinx]/[cosxcos(180x)tanx]
= [cosx(sin90cosxcos90sinx)sinx]/[cosx(cos180cosx+sinx180sinx)tanx]
= [cosx((1)cosx(0)sinx)sinx]/[cosx((1)cosx+(0)sinx)tanx]
= [cosxcosxsinx]/[cosx+cosxtanx]
= [cosx(1sinx]/[cosx(1+tanx]
= (1sinx)/(1+tanx)
Is this correct???

Trigonometry Check  Steve, Tuesday, February 21, 2012 at 11:31am
looks good to me
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