Posted by Elizabeth on Monday, February 20, 2012 at 9:10pm.
For the following reaction, Kp = 3.5 104 at 1495 K.
H2(g) + Br2(g) 2 HBr(g)
What is the value of Kp for the following reactions at 1495 K?
(a) HBr(g) 1/2 H2(g) + 1/2 Br2(g)
(b) 2 HBr(g) H2(g) + Br2(g)
(c) 1/2 H2(g) + 1/2 Br2(g) HBr(g)
Chemistry - DrBob222, Monday, February 20, 2012 at 9:19pm
For 1/2 the reaction, new k is sqrt Kp.
For 2 x reaction, new k is K^2p
For the reverse and 1/2 new k is 1/sqrt Kp.
Chemistry - Anonymous, Tuesday, March 1, 2016 at 11:04am
Chemistry - Anonymous, Saturday, February 18, 2017 at 4:00pm
- Reversing the direction of a reaction gives the inverse of the equilibrium constant.
- When multiplying by a constant, raise K to the power of that constant
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