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October 30, 2014

October 30, 2014

Posted by **mikey** on Monday, February 20, 2012 at 5:35pm.

- math -
**MathMate**, Monday, February 20, 2012 at 6:25pmAssuming the aquarium is to be filled to the top, 20" high less 3" of gravel,

volume of water V1 = 36*18*17 in^3.

Capacity of each bucket filled to 11" high

V2=π(6)^2*11=396π in^3

Number of buckets required = V1/V2

round to the next higher integer.

I get 9 buckets.

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