Sunday

April 20, 2014

April 20, 2014

Posted by **Jessica** on Monday, February 20, 2012 at 4:12pm.

- Physics -
**UNO**, Friday, February 22, 2013 at 10:46pmHey, Do your homework. Look at your notes and read the book. We are watching you.

Dr. C will not be happy.

- Physics -
**Erica**, Tuesday, February 25, 2014 at 11:17pmStatic Friction Coefficient = Cfs

For of Static Friction = Fs

Normal Force = Fn

Centripetal Force = Fc

mass = m

radius = r

speed = v

period of time = T

Fs = Cfs * Fn so Cfs = Fs/Fn

Fc = Fs and since Fs = mv^2/r

Cfs = Fs/Fn = mv^2/r*Fn

v = 2πr/T and Fn = mg

so....

mv^2 (2πr/T)^2 4(π^2)r

Cfs = ------ = ----------- = --------

rFn r(g) g(T^2)

4(π^2)(0.159 m)

Cfs = ------------------- = 0.28467

(9.8 m/s^2)(1.50 s)^2

*** Remember there are no units on coefficients***

- Physics -
**Erica**, Tuesday, February 25, 2014 at 11:21pmwell that doesn't look readable. the answer should still be right but I'll rewrite how I did the math

Cfs = mv^2/rFn = ((2πr/T)^2)/r(g) = (4(π^2)r)/g(T^2)

Cfs = 4(π^2)(0.159 m) / (9.8 m/s^2)(1.50 s)^2 =

0.28467

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