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January 26, 2015

January 26, 2015

Posted by **Anonymous** on Monday, February 20, 2012 at 2:21pm.

cscx(sin^2x+cos^2xtanx)/sinx+cosx

= cscx((1)tanx)/sinx+cosx

= cscxtanx/sinx+cosx

Is the correct answer cscxtanx/sinx+cosx?

Simplify #2:

sin2x/1+cos2X

= ???

I'm stuck on this one. I don't know what I should do.

Simplify #3:

cosx-sin(90-x)sinx/cosx-cos(180-x)tanx

= cosx-(sin90cosx-cos90sinx)sinx/cosx-(cos180cosx+sinx180sinx)tanx

= cosx-sin90cosx+cos90sinxsinx/cosx-cos180cosx-sinx180sinxtanx

= cosx-sin90cosx+cos90sin^2x/cosx-cos180cosx-sinx180sinxtanx

= ???

What do I do next?

Please help and Thank you

- Math 12 -
**MathGuru**, Monday, February 20, 2012 at 9:01pm#1:

Identities:

cscx = 1/sinx

tanx = sinx/cosx

Your answer can be simplified further using the above identities.

#2:

This one looks simplified as is.

#3:

I'll let someone else help you with this one.

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