Homework Help: Math 12

Posted by Anonymous on Monday, February 20, 2012 at 2:21pm.

Simplify #1:
cscx(sin^2x+cos^2xtanx)/sinx+cosx
= cscx((1)tanx)/sinx+cosx
= cscxtanx/sinx+cosx

Is the correct answer cscxtanx/sinx+cosx?

Simplify #2:
sin2x/1+cos2X
= ???

I'm stuck on this one. I don't know what I should do.

Simplify #3:
cosx-sin(90-x)sinx/cosx-cos(180-x)tanx
= cosx-(sin90cosx-cos90sinx)sinx/cosx-(cos180cosx+sinx180sinx)tanx
= cosx-sin90cosx+cos90sinxsinx/cosx-cos180cosx-sinx180sinxtanx
= cosx-sin90cosx+cos90sin^2x/cosx-cos180cosx-sinx180sinxtanx
= ???

What do I do next?

Please help and Thank you

Math 12 - MathGuru, Monday, February 20, 2012 at 9:01pm
#1:
Identities:
cscx = 1/sinx
tanx = sinx/cosx

Your answer can be simplified further using the above identities.

#2:
This one looks simplified as is.

#3:
I'll let someone else help you with this one.

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