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A 67.7 kg person jumps from rest off a 3.11 m-high tower straight down into the water. Neglect air resistance during the descent. She comes to rest 1.04 m under the surface of the water. Determine the magnitude of the average force that the water exerts on the diver. This force is nonconservative.

  • physics -

    Lost potential energy
    = M*g*(3.11 + 1.04)= M*g*(4.15 m)
    = work done against friction
    = Fav*(1.04 m)

    (There is zero kinetic energy at the beginning of the dive and the greatest underwater depth)

    Fav = (4.15/1.04)*M*g
    = 734 N

  • physics -

    2753.3 J

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