Posted by Judah on Monday, February 20, 2012 at 10:02am.
AX is the bisector of <BAC p is any point on AX. prove that the perpendicular drawn from Pto AB and AC are equal

MATHS  Steve, Monday, February 20, 2012 at 12:02pm
let pb and pc be the perpendiculars to AB and AC.
Since Ax is the angle bisector, angle XAB = XAC
using similar triangles,
pb/pa = pc/pa
so,
pb=pc
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