Posted by **Judah** on Monday, February 20, 2012 at 10:02am.

AX is the bisector of <BAC p is any point on AX. prove that the perpendicular drawn from Pto AB and AC are equal

- MATHS -
**Steve**, Monday, February 20, 2012 at 12:02pm
let pb and pc be the perpendiculars to AB and AC.

Since Ax is the angle bisector, angle XAB = XAC

using similar triangles,

pb/pa = pc/pa

so,

pb=pc

## Answer this Question

## Related Questions

- Maths - AX is the bisector of <BAC p is any point on AX. prove that the ...
- maths - In triangle ABC angle B > angle C if AM is the bisector of angle BAC...
- maths - ABC is a triangle with ∠BAC=60∘,AB=5 and AC=25. D is a point...
- Geometry - Can I get help starting this exercise:- Let triangle ABC be such that...
- maths - in triangle abc angle b = 2angle c.d is a point ob bc such that ad ...
- Math - Two conjugate diameters of the ellipse x^2/a^2+y^2/b^2=1 are drawn to ...
- Math - Please help me solve this question. Two conjugate diameters of the ...
- math - in triangle abc ad is bisector of angle a and angle b is twice of angle c...
- Geometry - BC is a triangle with ∠BAC=60∘,AB=5 and AC=25. D is a ...
- geometry - You have isosceles triangle WXY and segment WZ is the perpendicular ...

More Related Questions