Posted by **Judah** on Monday, February 20, 2012 at 10:02am.

AX is the bisector of <BAC p is any point on AX. prove that the perpendicular drawn from Pto AB and AC are equal

- MATHS -
**Steve**, Monday, February 20, 2012 at 12:02pm
let pb and pc be the perpendiculars to AB and AC.

Since Ax is the angle bisector, angle XAB = XAC

using similar triangles,

pb/pa = pc/pa

so,

pb=pc

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