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October 21, 2014

Homework Help: calculus

Posted by victoria on Monday, February 20, 2012 at 9:50am.

d/dx(e^sinx2x)=

a)-cos2xe^sinx2x
b)cosxe^sin2x
c)2e^sin2x
d)2cos2xe^sin2x
e)-2cos2xe^sin2x

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