If g'(x)=2g(x) and g(-1)=1, then g(x)=

a)e^2x
b)e^-x
c)e^(x+1)
d)e^(2x+2)
e)e^(2x-2)

Differentiate each choice and you will see than three (a,d,e) equal 2*g. Only one of those three satisfy

g(-1) = 1, however.