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March 26, 2017

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Determine h'(x) for h(x)= [x/(1-x)]^2

  • Calculus-derivatives - ,

    h(x) = [x/(1-x)]^2 = x^2 * (1-x)^-2

    h'(x) = 2x/(1-x)^2 +(-2)(-1)*x^2*(1-x)^-3
    = 2x/(1-x)^2 + 2x^2/(1-x)^3

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