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July 26, 2014

July 26, 2014

Posted by **UCI Student** on Monday, February 20, 2012 at 12:09am.

i really dont have any idea what to do...

- Calc -
**drwls**, Monday, February 20, 2012 at 5:17amThe relative velocity vector is

Vab = Va - Vb = -19*t i + 20t j

where i is a unit vector east and j is a unit vector north.

The magnitude of that vector is the rate of change of the distance between them, and is

|Vab| = sqrt[19^2 + 20^2] = 27.59 knots

That rate is a constant, and does not depend upon time of day nor the initital 40 n.m. separation. You have been given more information than you need.

The actual separation distance at any time DOES depend upon time and initial separation.

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