Posted by Anonymous on Sunday, February 19, 2012 at 11:45pm.
a) V^2/R = 0.520 m/s^2
V = 17.141 m/s
c) t = V/a = 32.963 s
b) S = (V/2)*t = 282.51 m
(measured along a circular arc)
It will have completed 0.499 radians of the track, or about 28.6 degrees
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