Posted by Peter on Sunday, February 19, 2012 at 10:36pm.
just undo the operations, one by one:
10^(2x^(2)-5x+11) = 10000
take log base 10
2x^(2)-5x+11 = log10000 = 4
2x^2 - 5x + 7 = 0
(2x-7)(x+1) = 0
. . .
9^(2(x-1)) = √(27) = 3^(3/2) = 9^(3/4)
take log base 9
2(x-1) = 3/4
8x-8 = 3
8x = 11
. . .
Related Questions
algebra 1 - alright i have a few questions if its ok..? Simplify: 1. -2&#...
Math - HELP?! 1.-9^2 2.(5x^9y)(-2x^-2y^-3) 3.(a^1b^-2) / (a^-2b^4) 4.(7x^-1/y^4...
math - 2x+4(1-x)=11+5x 2x+4-4x=11+5x 6x+4=11+5x 6x=7+5x x=7 i think this is it x...
maths - I will be thankfull to you if you help me to solve the below problem: 6&...
Math - Find an equation of the line that bisects the obtuse angles formed by the...
algebra/trig - 1. which number below is irrational? a)√4/9 b) &#...
math - The "x intercept" is where y = 0, which is where the curve ...
Algebra-please check my answers - Solve the equation by expressing each side as ...
math - 1-AND PRODUCTION sum of roots of the equation :X²-X-6=0 2-FOR what ...
algebra 2 - i need help with these questions simplify √4x^2/y^3 &#...
For Further Reading
