Algebra 2
posted by Peter .
Solve each equation below for x. (Use logarithms.)
10^(2x^(2)5x+11) = 10000
9^(2(x1)) = √(27)

just undo the operations, one by one:
10^(2x^(2)5x+11) = 10000
take log base 10
2x^(2)5x+11 = log10000 = 4
2x^2  5x + 7 = 0
(2x7)(x+1) = 0
. . .
9^(2(x1)) = √(27) = 3^(3/2) = 9^(3/4)
take log base 9
2(x1) = 3/4
8x8 = 3
8x = 11
. . .