Homework Help: physics

Posted by Shelby on Sunday, February 19, 2012 at 8:56pm.

A car (m = 1540 kg) is parked on a road that rises 18.9 ° above the horizontal. What are the magnitudes of (a) the normal force and (b) the static frictional force that the ground exerts on the tires?

physics - Henry, Tuesday, February 21, 2012 at 8:10pm
Wc = mg = 1540kg * 9.8N/kg = 15,092 N. = Wt of car.

Fc = 15092N. @ 18.9 Deg.
Fp = 15092*sin18.9 Deg. = 4889 N. = Force parallel to road.

a. Fv = 15092*cos18.9 = 14,278 N. = Force perpendicular to road = The normal.

b. Fn = Fp - Fs = 0,
4889 - Fs = 0,
Fs = 4889 N. = Force of static friction.

Answer this Question

Related Questions

Physics - A car (m = 1510 kg) is parked on a road that rises 12.6 ° above ...
physics - A car (m = 1670 kg) is parked on a road that rises 10.3 ° above ...
Physics - A Mercedes-Benz 300SL (m = 1700 kg) is parked on a road that rises 15&...
physics - 2. A car of mass 1540 kg traveling at 28 m/s is at the foot of a hill ...
physics - A 1,660 kg car is parked on a hill with a slope of 8.0°. Its ...
Physics. PLEASE HELP!! - A small car of mass 985 kg is parked behind a small ...
Physics - A 2050 kg car rounds a circular turn of radius 18.5 m. If the road is ...
math - six cars are parked in front of a car dealership. If you are looking at ...
physics - a driver wants his car to jump over cars parked below him. He drives ...
Physics - A 1100 kg car is moving toward the north along a straight road at a ...

For Further Reading

First Name:
School Subject:
Answer: