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posted by Billy Sunday, February 19, 2012 at 8:39pm.
if g(x) varies exponentially with x, and g(0) =37 and g(7) =5940 find the particular equation...
g = ka^x 37 = ka^0 = k so, g = 37a^x 5940 = 37a^7 160.54 = a^7 a = 2.066 g = 37*2.066^x
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