Posted by Toney on Sunday, February 19, 2012 at 8:30pm.
A rectangular parcel of land is 70 ft longer than it is wide. Each diagonal between opposite corners is 130 ft. What are the dimensions of the parcel?

Math  Steve, Sunday, February 19, 2012 at 8:43pm
sides are x and x+70
x^2 + (x+70)^2 = 130^2
x^2 + x^2 + 140x + 4900 = 16900
2x^2 + 140x  12000 = 0
x^2 + 70x  6000 = 0
(x+120)(x50) = 0
x = 50
sides are 50, 120
Or, more easily, you could have checked for a scaledup 5,12,13 triangle. The diagonal of 130 was a good hint.
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