Posted by **Toney** on Sunday, February 19, 2012 at 8:30pm.

A rectangular parcel of land is 70 ft longer than it is wide. Each diagonal between opposite corners is 130 ft. What are the dimensions of the parcel?

- Math -
**Steve**, Sunday, February 19, 2012 at 8:43pm
sides are x and x+70

x^2 + (x+70)^2 = 130^2

x^2 + x^2 + 140x + 4900 = 16900

2x^2 + 140x - 12000 = 0

x^2 + 70x - 6000 = 0

(x+120)(x-50) = 0

x = 50

sides are 50, 120

Or, more easily, you could have checked for a scaled-up 5,12,13 triangle. The diagonal of 130 was a good hint.

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