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April 16, 2014

April 16, 2014

Posted by **Wally** on Sunday, February 19, 2012 at 5:04pm.

P(t) = 100/1+48.2e^-0.52t

If the company's claim is true, how many months will it take to have mastered 80% of the program.

I just need help setting it up

Thanks!

- Math -
**Reiny**, Sunday, February 19, 2012 at 5:26pmI will assume you meant

P(t) = 100/(1+48.2e^(-.52t) )

You did not define P(t), but I will assume it will be the

"efficiency" mastered after t months

so .....

.8 = 100/(1 + 48.2e^(.52t))

.8 + 38.56e^(.52t) = 100

e^(.52t) = (100-.8)/38.56 = 2.572614

taking ln of both sides, and knowing that ln e = 1

.52t = ln (2.572614)

t = 1.817 or appr 1.8 months

check:

let t=1.817

P(1.1817) = 100/(1 + 48.2e^(.52(1.817)

= 0.8

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